a-[2a-[b-(3a-2a)]]=0

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Solution for a-[2a-[b-(3a-2a)]]=0 equation:


Simplifying
a + -1[2a + -1[b + -1(3a + -2a)]] = 0

Combine like terms: 3a + -2a = 1a
a + -1[2a + -1[b + -1(1a)]] = 0

Remove parenthesis around (1a)
a + -1[2a + -1[b + -1 * 1a]] = 0

Multiply -1 * 1
a + -1[2a + -1[b + -1a]] = 0

Reorder the terms:
a + -1[2a + -1[-1a + b]] = 0
a + -1[2a + [-1a * -1 + b * -1]] = 0
a + -1[2a + [1a + -1b]] = 0

Combine like terms: 2a + 1a = 3a
a + -1[3a + -1b] = 0
a + [3a * -1 + -1b * -1] = 0
a + [-3a + 1b] = 0

Combine like terms: a + -3a = -2a
-2a + 1b = 0

Solving
-2a + 1b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1b' to each side of the equation.
-2a + 1b + -1b = 0 + -1b

Combine like terms: 1b + -1b = 0
-2a + 0 = 0 + -1b
-2a = 0 + -1b
Remove the zero:
-2a = -1b

Divide each side by '-2'.
a = 0.5b

Simplifying
a = 0.5b

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